3.15.5 \(\int \frac {(2+3 x)^2 (3+5 x)}{(1-2 x)^2} \, dx\)

Optimal. Leaf size=32 \[ \frac {45 x^2}{8}+33 x+\frac {539}{16 (1-2 x)}+\frac {707}{16} \log (1-2 x) \]

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Rubi [A]  time = 0.02, antiderivative size = 32, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.050, Rules used = {77} \begin {gather*} \frac {45 x^2}{8}+33 x+\frac {539}{16 (1-2 x)}+\frac {707}{16} \log (1-2 x) \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((2 + 3*x)^2*(3 + 5*x))/(1 - 2*x)^2,x]

[Out]

539/(16*(1 - 2*x)) + 33*x + (45*x^2)/8 + (707*Log[1 - 2*x])/16

Rule 77

Int[((a_.) + (b_.)*(x_))*((c_) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandIntegran
d[(a + b*x)*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, n}, x] && NeQ[b*c - a*d, 0] && ((ILtQ[
n, 0] && ILtQ[p, 0]) || EqQ[p, 1] || (IGtQ[p, 0] && ( !IntegerQ[n] || LeQ[9*p + 5*(n + 2), 0] || GeQ[n + p + 1
, 0] || (GeQ[n + p + 2, 0] && RationalQ[a, b, c, d, e, f]))))

Rubi steps

\begin {align*} \int \frac {(2+3 x)^2 (3+5 x)}{(1-2 x)^2} \, dx &=\int \left (33+\frac {45 x}{4}+\frac {539}{8 (-1+2 x)^2}+\frac {707}{8 (-1+2 x)}\right ) \, dx\\ &=\frac {539}{16 (1-2 x)}+33 x+\frac {45 x^2}{8}+\frac {707}{16} \log (1-2 x)\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 36, normalized size = 1.12 \begin {gather*} \frac {360 x^3+1932 x^2-2202 x+1414 (2 x-1) \log (1-2 x)-505}{64 x-32} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((2 + 3*x)^2*(3 + 5*x))/(1 - 2*x)^2,x]

[Out]

(-505 - 2202*x + 1932*x^2 + 360*x^3 + 1414*(-1 + 2*x)*Log[1 - 2*x])/(-32 + 64*x)

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {(2+3 x)^2 (3+5 x)}{(1-2 x)^2} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[((2 + 3*x)^2*(3 + 5*x))/(1 - 2*x)^2,x]

[Out]

IntegrateAlgebraic[((2 + 3*x)^2*(3 + 5*x))/(1 - 2*x)^2, x]

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fricas [A]  time = 1.49, size = 37, normalized size = 1.16 \begin {gather*} \frac {180 \, x^{3} + 966 \, x^{2} + 707 \, {\left (2 \, x - 1\right )} \log \left (2 \, x - 1\right ) - 528 \, x - 539}{16 \, {\left (2 \, x - 1\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^2*(3+5*x)/(1-2*x)^2,x, algorithm="fricas")

[Out]

1/16*(180*x^3 + 966*x^2 + 707*(2*x - 1)*log(2*x - 1) - 528*x - 539)/(2*x - 1)

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giac [A]  time = 0.98, size = 48, normalized size = 1.50 \begin {gather*} \frac {3}{32} \, {\left (2 \, x - 1\right )}^{2} {\left (\frac {206}{2 \, x - 1} + 15\right )} - \frac {539}{16 \, {\left (2 \, x - 1\right )}} - \frac {707}{16} \, \log \left (\frac {{\left | 2 \, x - 1 \right |}}{2 \, {\left (2 \, x - 1\right )}^{2}}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^2*(3+5*x)/(1-2*x)^2,x, algorithm="giac")

[Out]

3/32*(2*x - 1)^2*(206/(2*x - 1) + 15) - 539/16/(2*x - 1) - 707/16*log(1/2*abs(2*x - 1)/(2*x - 1)^2)

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maple [A]  time = 0.01, size = 27, normalized size = 0.84 \begin {gather*} \frac {45 x^{2}}{8}+33 x +\frac {707 \ln \left (2 x -1\right )}{16}-\frac {539}{16 \left (2 x -1\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((3*x+2)^2*(5*x+3)/(1-2*x)^2,x)

[Out]

45/8*x^2+33*x-539/16/(2*x-1)+707/16*ln(2*x-1)

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maxima [A]  time = 0.68, size = 26, normalized size = 0.81 \begin {gather*} \frac {45}{8} \, x^{2} + 33 \, x - \frac {539}{16 \, {\left (2 \, x - 1\right )}} + \frac {707}{16} \, \log \left (2 \, x - 1\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^2*(3+5*x)/(1-2*x)^2,x, algorithm="maxima")

[Out]

45/8*x^2 + 33*x - 539/16/(2*x - 1) + 707/16*log(2*x - 1)

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mupad [B]  time = 0.03, size = 24, normalized size = 0.75 \begin {gather*} 33\,x+\frac {707\,\ln \left (x-\frac {1}{2}\right )}{16}-\frac {539}{32\,\left (x-\frac {1}{2}\right )}+\frac {45\,x^2}{8} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((3*x + 2)^2*(5*x + 3))/(2*x - 1)^2,x)

[Out]

33*x + (707*log(x - 1/2))/16 - 539/(32*(x - 1/2)) + (45*x^2)/8

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sympy [A]  time = 0.10, size = 26, normalized size = 0.81 \begin {gather*} \frac {45 x^{2}}{8} + 33 x + \frac {707 \log {\left (2 x - 1 \right )}}{16} - \frac {539}{32 x - 16} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)**2*(3+5*x)/(1-2*x)**2,x)

[Out]

45*x**2/8 + 33*x + 707*log(2*x - 1)/16 - 539/(32*x - 16)

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